Going Airborne
Problem Solving
practitioner
Problem Solving Rationale
<p>The student’s initial strategy of finding common denominators to compare the distance traveled for each character (252) could work to solve the task. The student correctly determines that Peter Pan will take 1 hour and 45 minutes to travel around the world, Aladdin will take 1 hour 36 minutes, and the Wicked Witch will take 1 hour 30 minutes and concludes that the Wicked Witch will travel around the world's fastest. However, the strategy used to reach this solution is not evident.</p>
Reasoning and Proof
apprentice
Reasoning Proof Rationale
<p>The student demonstrates some understanding of the concept of unit rates associated with ratios of fractions. The student correctly determines the distance traveled around the world by each character’s first interval using common denominators. The final solution is correct. The student however provides no mathematical justification for his/her conclusions for how much time it would take each character to complete the race. </p>
Communication Level
apprentice
Communication Rationale
<p>The student provides a clear purpose for the problem in his/her opening sentence. The student attempts to explain his/her initial approach of finding common denominators, but the mathematical argument lacks detail and significant interpretation of the required approach. The student does not provide his/her approach to how the time traveled was converted into minutes or how the exact time to travel completely around the world was calculated. The student correctly uses formal math language, including fastest, distance, common denominators, minutes, hour, and constant pace.</p>
Connections Level
practitioner
Connections RationaleGoing Airborne
<p>The student identifies an important situational context within the task when he/she states that “<i>this is all assuming that they each of them keep a constant pace</i>.”</p>
Representation
practitioner
Representation Rationale
<p>The student constructs a table which accurately portrays his/her solutions to the time and distances traveled by each of the contenders in the problem.</p>